15x^2+43x-44=0

Solution for 15x^2+43x-44=0 equation:

15x^2+43x-44=0

a = 15; b = 43; c = -44;
Δ = b2-4ac
Δ = 432-4·15·(-44)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4489}=67$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-67}{2*15}=\frac{-110}{30}
=-3+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+67}{2*15}=\frac{24}{30}
=4/5
$